16x^2-48x+36=25

Solution for 16x^2-48x+36=25 equation:

16x^2-48x+36=25

We move all terms to the left:

16x^2-48x+36-(25)=0

We add all the numbers together, and all the variables

16x^2-48x+11=0

a = 16; b = -48; c = +11;
Δ = b2-4ac
Δ = -482-4·16·11
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-40}{2*16}=\frac{8}{32}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+40}{2*16}=\frac{88}{32}
=2+3/4
$